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113110300212120 = 23325314195278367
BaseRepresentation
bin11001101101111110001011…
…010000111011101110011000
3112211111020110022010101112200
4121231332023100323232120
5104311144343323241440
61040322053215410200
732552643453226251
oct3155761320735630
9484436408111480
10113110300212120
1133049899765872
121082964a823960
134b16342571763
141dd07d3c47b28
15d123d25a0c30
hex66df8b43bb98

113110300212120 has 48 divisors (see below), whose sum is σ = 367608475690560. Its totient is φ = 30162746723136.

The previous prime is 113110300212101. The next prime is 113110300212127. The reversal of 113110300212120 is 21212003011311.

113110300212120 is a `hidden beast` number, since 1 + 1 + 31 + 1 + 0 + 300 + 212 + 120 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 113110300212093 and 113110300212102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113110300212127) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 157097638824 + ... + 157097639543.

It is an arithmetic number, because the mean of its divisors is an integer number (7658509910220).

Almost surely, 2113110300212120 is an apocalyptic number.

113110300212120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113110300212120 is an abundant number, since it is smaller than the sum of its proper divisors (254498175478440).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113110300212120 is a wasteful number, since it uses less digits than its factorization.

113110300212120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 314195278384 (or 314195278377 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 113110300212120 its reverse (21212003011311), we get a palindrome (134322303223431).

The spelling of 113110300212120 in words is "one hundred thirteen trillion, one hundred ten billion, three hundred million, two hundred twelve thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 18 20 24 30 36 40 45 60 72 90 120 180 360 314195278367 628390556734 942585835101 1256781113468 1570976391835 1885171670202 2513562226936 2827757505303 3141952783670 3770343340404 4712929175505 5655515010606 6283905567340 7540686680808 9425858351010 11311030021212 12567811134680 14138787526515 18851716702020 22622060042424 28277575053030 37703433404040 56555150106060 113110300212120