11311101344430 has 24 divisors (see below), whose sum is σ = 29408863495752. Its totient is φ = 3016293691824.

The previous prime is 11311101344393. The next prime is 11311101344437. The reversal of 11311101344430 is 3444310111311.

11311101344430 is a `hidden beast` number, since 1 + 1 + 311 + 1 + 0 + 1 + 344 + 4 + 3 + 0 = 666.

11311101344430 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11311101344394 and 11311101344403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11311101344437) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 62839451824 + ... + 62839452003.

It is an arithmetic number, because the mean of its divisors is an integer number (1225369312323).

Almost surely, 2^{11311101344430} is an apocalyptic number.

11311101344430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11311101344430 is an abundant number, since it is smaller than the sum of its proper divisors (18097762151322).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11311101344430 is a wasteful number, since it uses less digits than its factorization.

11311101344430 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 125678903840 (or 125678903837 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 11311101344430 its reverse (3444310111311), we get a palindrome (14755411455741).

The spelling of 11311101344430 in words is "eleven trillion, three hundred eleven billion, one hundred one million, three hundred forty-four thousand, four hundred thirty".