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11311103009981 is a prime number
BaseRepresentation
bin1010010010011001001001…
…0001101110010010111101
31111001022221012212001102102
42210212102101232102331
52440310114332304411
640020125440434445
72245125451141325
oct244462221562275
944038835761372
1011311103009981
113671014850a15
121328201618a25
1364082b605b48
142b1663120285
151493639a3d3b
hexa499246e4bd

11311103009981 has 2 divisors, whose sum is σ = 11311103009982. Its totient is φ = 11311103009980.

The previous prime is 11311103009959. The next prime is 11311103010019. The reversal of 11311103009981 is 18990030111311.

It is an a-pointer prime, because the next prime (11311103010019) can be obtained adding 11311103009981 to its sum of digits (38).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6051575400025 + 5259527609956 = 2459995^2 + 2293366^2 .

It is a cyclic number.

It is not a de Polignac number, because 11311103009981 - 218 = 11311102747837 is a prime.

It is a super-2 number, since 2×113111030099812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311103009281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655551504990 + 5655551504991.

It is an arithmetic number, because the mean of its divisors is an integer number (5655551504991).

Almost surely, 211311103009981 is an apocalyptic number.

It is an amenable number.

11311103009981 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311103009981 is an equidigital number, since it uses as much as digits as its factorization.

11311103009981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 38.

The spelling of 11311103009981 in words is "eleven trillion, three hundred eleven billion, one hundred three million, nine thousand, nine hundred eighty-one".