Base | Representation |
---|---|
bin | 10101000100011001… |
… | …10110000111000111 |
3 | 1002012022001001101221 |
4 | 22202030312013013 |
5 | 141131132222301 |
6 | 5110222301211 |
7 | 550205464255 |
oct | 124214660707 |
9 | 32168031357 |
10 | 11311210951 |
11 | 488497a227 |
12 | 2238127807 |
13 | 10b354c241 |
14 | 7943615d5 |
15 | 463064da1 |
hex | 2a23361c7 |
11311210951 has 2 divisors, whose sum is σ = 11311210952. Its totient is φ = 11311210950.
The previous prime is 11311210949. The next prime is 11311211027. The reversal of 11311210951 is 15901211311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11311210951 - 21 = 11311210949 is a prime.
It is a super-3 number, since 3×113112109513 (a number of 31 digits) contains 333 as substring.
Together with 11311210949, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11311210051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655605475 + 5655605476.
It is an arithmetic number, because the mean of its divisors is an integer number (5655605476).
Almost surely, 211311210951 is an apocalyptic number.
11311210951 is a deficient number, since it is larger than the sum of its proper divisors (1).
11311210951 is an equidigital number, since it uses as much as digits as its factorization.
11311210951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 270, while the sum is 25.
The spelling of 11311210951 in words is "eleven billion, three hundred eleven million, two hundred ten thousand, nine hundred fifty-one".
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