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11311401391 is a prime number
BaseRepresentation
bin10101000100011011…
…00100100110101111
31002012022101201122021
422202031210212233
5141131204321031
65110230331011
7550210216423
oct124215444657
932168351567
1011311401391
114884a9a314
1222381b9a67
1310b35b7b24
147943b0b83
154630a1511
hex2a23649af

11311401391 has 2 divisors, whose sum is σ = 11311401392. Its totient is φ = 11311401390.

The previous prime is 11311401389. The next prime is 11311401443. The reversal of 11311401391 is 19310411311.

11311401391 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (19310411311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11311401391 - 21 = 11311401389 is a prime.

Together with 11311401389, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11311401331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5655700695 + 5655700696.

It is an arithmetic number, because the mean of its divisors is an integer number (5655700696).

Almost surely, 211311401391 is an apocalyptic number.

11311401391 is a deficient number, since it is larger than the sum of its proper divisors (1).

11311401391 is an equidigital number, since it uses as much as digits as its factorization.

11311401391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 25.

The spelling of 11311401391 in words is "eleven billion, three hundred eleven million, four hundred one thousand, three hundred ninety-one".