Base | Representation |
---|---|
bin | 100001101101100… |
… | …1100001100010100 |
3 | 2220211112222110110 |
4 | 1003123030030110 |
5 | 4304041420200 |
6 | 304125323020 |
7 | 40014023655 |
oct | 10333141424 |
9 | 2824488413 |
10 | 1131201300 |
11 | 530596309 |
12 | 276a06470 |
13 | 1504866a8 |
14 | aa34152c |
15 | 6949ab50 |
hex | 436cc314 |
1131201300 has 72 divisors (see below), whose sum is σ = 3281908000. Its totient is φ = 300827520.
The previous prime is 1131201299. The next prime is 1131201329. The reversal of 1131201300 is 31021311.
It is a super-2 number, since 2×11312013002 = 2559232762243380000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 108726 + ... + 118674.
Almost surely, 21131201300 is an apocalyptic number.
1131201300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1131201300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1640954000).
1131201300 is an abundant number, since it is smaller than the sum of its proper divisors (2150706700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1131201300 is a wasteful number, since it uses less digits than its factorization.
1131201300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10345 (or 10338 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 12.
The square root of 1131201300 is about 33633.3361413940. The cubic root of 1131201300 is about 1041.9494070531.
Adding to 1131201300 its reverse (31021311), we get a palindrome (1162222611).
The spelling of 1131201300 in words is "one billion, one hundred thirty-one million, two hundred one thousand, three hundred".
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