113120323207 has 2 divisors, whose sum is σ = 113120323208. Its totient is φ = 113120323206.

The previous prime is 113120323187. The next prime is 113120323231. The reversal of 113120323207 is 702323021311.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (702323021311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-113120323207 is a prime.

It is a super-3 number, since 3×113120323207³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113120323247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56560161603 + 56560161604.

It is an arithmetic number, because the mean of its divisors is an integer number (56560161604).

Almost surely, 2^113120323207 is an apocalyptic number.

113120323207 is a deficient number, since it is larger than the sum of its proper divisors (1).

113120323207 is an equidigital number, since it uses as much as digits as its factorization.

113120323207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 113120323207 its reverse (702323021311), we get a palindrome (815443344518).

The spelling of 113120323207 in words is "one hundred thirteen billion, one hundred twenty million, three hundred twenty-three thousand, two hundred seven".