11312101319 has 2 divisors, whose sum is σ = 11312101320. Its totient is φ = 11312101318.

The previous prime is 11312101313. The next prime is 11312101321. The reversal of 11312101319 is 91310121311.

It is a happy number.

11312101319 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11312101319 - 2²⁸ = 11043665863 is a prime.

It is a super-2 number, since 2×11312101319² (a number of 21 digits) contains 22 as substring.

Together with 11312101321, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11312101294 and 11312101303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312101313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656050659 + 5656050660.

It is an arithmetic number, because the mean of its divisors is an integer number (5656050660).

Almost surely, 2^11312101319 is an apocalyptic number.

11312101319 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312101319 is an equidigital number, since it uses as much as digits as its factorization.

11312101319 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 23.

The spelling of 11312101319 in words is "eleven billion, three hundred twelve million, one hundred one thousand, three hundred nineteen".