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11312333110229 is a prime number
BaseRepresentation
bin1010010010011101101110…
…0110001011101111010101
31111001110002221111121201212
42210213123212023233111
52440320124234011404
640020451502031205
72245201105623404
oct244473346135725
944043087447655
1011312333110229
113671596146498
1213284a5578505
13640996408b08
142b173c64763b
151493d698806e
hexa49db98bbd5

11312333110229 has 2 divisors, whose sum is σ = 11312333110230. Its totient is φ = 11312333110228.

The previous prime is 11312333110193. The next prime is 11312333110231. The reversal of 11312333110229 is 92201133321311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9444127996900 + 1868205113329 = 3073130^2 + 1366823^2 .

It is a cyclic number.

It is not a de Polignac number, because 11312333110229 - 224 = 11312316333013 is a prime.

Together with 11312333110231, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11312333110195 and 11312333110204.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11312333110289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656166555114 + 5656166555115.

It is an arithmetic number, because the mean of its divisors is an integer number (5656166555115).

Almost surely, 211312333110229 is an apocalyptic number.

It is an amenable number.

11312333110229 is a deficient number, since it is larger than the sum of its proper divisors (1).

11312333110229 is an equidigital number, since it uses as much as digits as its factorization.

11312333110229 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 32.

The spelling of 11312333110229 in words is "eleven trillion, three hundred twelve billion, three hundred thirty-three million, one hundred ten thousand, two hundred twenty-nine".