Base | Representation |
---|---|
bin | 11001101110001011000100… |
… | …010000111101001100000000 |
3 | 112211112120011220210200002011 |
4 | 121232023010100331030000 |
5 | 104311411220200440222 |
6 | 1040332302500502304 |
7 | 32553643452452650 |
oct | 3156130420751400 |
9 | 484476156720064 |
10 | 113124141421312 |
11 | 3305475176812a |
12 | 108302720aa994 |
13 | 4b17739cc4378 |
14 | 1dd13481c8360 |
15 | d129427b9c77 |
hex | 66e2c443d300 |
113124141421312 has 72 divisors (see below), whose sum is σ = 258118421689856. Its totient is φ = 48471634953216.
The previous prime is 113124141421253. The next prime is 113124141421363. The reversal of 113124141421312 is 213124141421311.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1972003 + ... + 15170269.
Almost surely, 2113124141421312 is an apocalyptic number.
It is an amenable number.
113124141421312 is an abundant number, since it is smaller than the sum of its proper divisors (144994280268544).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113124141421312 is an equidigital number, since it uses as much as digits as its factorization.
113124141421312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13203073 (or 13203059 counting only the distinct ones).
The product of its digits is 4608, while the sum is 31.
Adding to 113124141421312 its reverse (213124141421311), we get a palindrome (326248282842623).
Subtracting 113124141421312 from its reverse (213124141421311), we obtain a palindrome (99999999999999).
The spelling of 113124141421312 in words is "one hundred thirteen trillion, one hundred twenty-four billion, one hundred forty-one million, four hundred twenty-one thousand, three hundred twelve".
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