Base | Representation |
---|---|
bin | 10000011101100011010… |
… | …111100001100101110010 |
3 | 11000010221022020112022121 |
4 | 100131203113201211302 |
5 | 122013241314311010 |
6 | 2223404110224454 |
7 | 144505161116236 |
oct | 20354327414562 |
9 | 4003838215277 |
10 | 1131243510130 |
11 | 3a6837519648 |
12 | 1632ab1b512a |
13 | 828a2989c86 |
14 | 3ca76b2a5c6 |
15 | 1e65d85c3da |
hex | 107635e1972 |
1131243510130 has 32 divisors (see below), whose sum is σ = 2156550836400. Its totient is φ = 425774469120.
The previous prime is 1131243510121. The next prime is 1131243510191. The reversal of 1131243510130 is 310153421311.
It can be written as a sum of positive squares in 8 ways, for example, as 881452466449 + 249791043681 = 938857^2 + 499791^2 .
It is a super-2 number, since 2×11312435101302 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1131243510095 and 1131243510104.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 133401 + ... + 1510060.
Almost surely, 21131243510130 is an apocalyptic number.
1131243510130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1131243510130 is a deficient number, since it is larger than the sum of its proper divisors (1025307326270).
1131243510130 is a wasteful number, since it uses less digits than its factorization.
1131243510130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1647534.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 1131243510130 its reverse (310153421311), we get a palindrome (1441396931441).
The spelling of 1131243510130 in words is "one trillion, one hundred thirty-one billion, two hundred forty-three million, five hundred ten thousand, one hundred thirty".
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