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113130020311110 = 232511114272747789
BaseRepresentation
bin11001101110010000100010…
…101011001001000001000110
3112211120010100121222012210100
4121232100202223021001012
5104312010240144423420
61040335114105504530
732554242236264235
oct3156204253110106
9484503317865710
10113130020311110
1133057199199040
1210831432aa2146
134b18165c67a9a
141dd1744cacb1c
15d12b8897d190
hex66e422ac9046

113130020311110 has 48 divisors (see below), whose sum is σ = 320877875794320. Its totient is φ = 27425459469120.

The previous prime is 113130020311093. The next prime is 113130020311123. The reversal of 113130020311110 is 11113020031311.

113130020311110 is a `hidden beast` number, since 1 + 1 + 31 + 300 + 20 + 311 + 1 + 1 + 0 = 666.

It is a super-2 number, since 2×1131300203111102 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 57136372905 + ... + 57136374884.

It is an arithmetic number, because the mean of its divisors is an integer number (6684955745715).

Almost surely, 2113130020311110 is an apocalyptic number.

113130020311110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113130020311110 is an abundant number, since it is smaller than the sum of its proper divisors (207747855483210).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113130020311110 is a wasteful number, since it uses less digits than its factorization.

113130020311110 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 114272747813 (or 114272747810 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 113130020311110 its reverse (11113020031311), we get a palindrome (124243040342421).

The spelling of 113130020311110 in words is "one hundred thirteen trillion, one hundred thirty billion, twenty million, three hundred eleven thousand, one hundred ten".

Divisors: 1 2 3 5 6 9 10 11 15 18 22 30 33 45 55 66 90 99 110 165 198 330 495 990 114272747789 228545495578 342818243367 571363738945 685636486734 1028454730101 1142727477890 1257000225679 1714091216835 2056909460202 2514000451358 3428182433670 3771000677037 5142273650505 6285001128395 7542001354074 10284547301010 11313002031111 12570002256790 18855003385185 22626004062222 37710006770370 56565010155555 113130020311110