11313011221333 has 2 divisors, whose sum is σ = 11313011221334. Its totient is φ = 11313011221332.

The previous prime is 11313011221301. The next prime is 11313011221339. The reversal of 11313011221333 is 33312211031311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7957234214449 + 3355777006884 = 2820857^2 + 1831878^2 .

It is an emirp because it is prime and its reverse (33312211031311) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11313011221333 - 2⁵ = 11313011221301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11313011221298 and 11313011221307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11313011221339) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5656505610666 + 5656505610667.

It is an arithmetic number, because the mean of its divisors is an integer number (5656505610667).

Almost surely, 2^{11313011221333} is an apocalyptic number.

It is an amenable number.

11313011221333 is a deficient number, since it is larger than the sum of its proper divisors (1).

11313011221333 is an equidigital number, since it uses as much as digits as its factorization.

11313011221333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11313011221333 its reverse (33312211031311), we get a palindrome (44625222252644).

The spelling of 11313011221333 in words is "eleven trillion, three hundred thirteen billion, eleven million, two hundred twenty-one thousand, three hundred thirty-three".