Base | Representation |
---|---|
bin | 10000011101101000000… |
… | …000010101101001011111 |
3 | 11000011010201122120121221 |
4 | 100131220000111221133 |
5 | 122013421224133413 |
6 | 2223415530034211 |
7 | 144510124352263 |
oct | 20355000255137 |
9 | 4004121576557 |
10 | 1131321317983 |
11 | 3a687743285a |
12 | 163311278967 |
13 | 828b5b3061c |
14 | 3ca831c20a3 |
15 | 1e6655cb68d |
hex | 10768015a5f |
1131321317983 has 2 divisors, whose sum is σ = 1131321317984. Its totient is φ = 1131321317982.
The previous prime is 1131321317981. The next prime is 1131321318037. The reversal of 1131321317983 is 3897131231311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1131321317983 - 21 = 1131321317981 is a prime.
Together with 1131321317981, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131321317981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565660658991 + 565660658992.
It is an arithmetic number, because the mean of its divisors is an integer number (565660658992).
Almost surely, 21131321317983 is an apocalyptic number.
1131321317983 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131321317983 is an equidigital number, since it uses as much as digits as its factorization.
1131321317983 is an evil number, because the sum of its binary digits is even.
The product of its digits is 81648, while the sum is 43.
The spelling of 1131321317983 in words is "one trillion, one hundred thirty-one billion, three hundred twenty-one million, three hundred seventeen thousand, nine hundred eighty-three".
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