Base | Representation |
---|---|
bin | 100001101101110… |
… | …1110010011110111 |
3 | 2220211211002011021 |
4 | 1003123232103313 |
5 | 4304110403142 |
6 | 304132322011 |
7 | 40015145254 |
oct | 10333562367 |
9 | 2824732137 |
10 | 1131341047 |
11 | 530681301 |
12 | 276a73307 |
13 | 150505195 |
14 | aa37a42b |
15 | 694c7267 |
hex | 436ee4f7 |
1131341047 has 2 divisors, whose sum is σ = 1131341048. Its totient is φ = 1131341046.
The previous prime is 1131341009. The next prime is 1131341083. The reversal of 1131341047 is 7401431311.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (7401431311) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1131341047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1131341147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565670523 + 565670524.
It is an arithmetic number, because the mean of its divisors is an integer number (565670524).
Almost surely, 21131341047 is an apocalyptic number.
1131341047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1131341047 is an equidigital number, since it uses as much as digits as its factorization.
1131341047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 25.
The square root of 1131341047 is about 33635.4135844945. The cubic root of 1131341047 is about 1041.9923122690.
Adding to 1131341047 its reverse (7401431311), we get a palindrome (8532772358).
The spelling of 1131341047 in words is "one billion, one hundred thirty-one million, three hundred forty-one thousand, forty-seven".
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