113140032424000 has 56 divisors (see below), whose sum is σ = 280191290317848. Its totient is φ = 45256012966400.

The previous prime is 113140032423973. The next prime is 113140032424009. The reversal of 113140032424000 is 424230041311.

It can be written as a sum of positive squares in 4 ways, for example, as 5180285248576 + 107959747175424 = 2276024^2 + 10390368^2 .

It is a super-3 number, since 3×113140032424000³ (a number of 43 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (113140032424009) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7071244027 + ... + 7071260026.

It is an arithmetic number, because the mean of its divisors is an integer number (5003415898533).

Almost surely, 2^{113140032424000} is an apocalyptic number.

113140032424000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113140032424000 is an abundant number, since it is smaller than the sum of its proper divisors (167051257893848).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113140032424000 is an equidigital number, since it uses as much as digits as its factorization.

113140032424000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14142504080 (or 14142504060 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 113140032424000 its reverse (424230041311), we get a palindrome (113564262465311).

The spelling of 113140032424000 in words is "one hundred thirteen trillion, one hundred forty billion, thirty-two million, four hundred twenty-four thousand".