Base | Representation |
---|---|
bin | 1010010010100100000011… |
… | …0100110100000001000011 |
3 | 1111001121111022012220201221 |
4 | 2210221000310310001003 |
5 | 2440332114022202120 |
6 | 40021332211135511 |
7 | 2245261150336045 |
oct | 244510064640103 |
9 | 44047438186657 |
10 | 11314031444035 |
11 | 3672287880851 |
12 | 132889a2a4597 |
13 | 640ba7220b68 |
14 | 2b1860017a95 |
15 | 149485b0d0aa |
hex | a4a40d34043 |
11314031444035 has 32 divisors (see below), whose sum is σ = 13740510168000. Its totient is φ = 8942616055296.
The previous prime is 11314031444003. The next prime is 11314031444057. The reversal of 11314031444035 is 53044413041311.
It is a cyclic number.
It is not a de Polignac number, because 11314031444035 - 25 = 11314031444003 is a prime.
It is a super-2 number, since 2×113140314440352 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 322604481 + ... + 322639549.
It is an arithmetic number, because the mean of its divisors is an integer number (429390942750).
Almost surely, 211314031444035 is an apocalyptic number.
11314031444035 is a deficient number, since it is larger than the sum of its proper divisors (2426478723965).
11314031444035 is a wasteful number, since it uses less digits than its factorization.
11314031444035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36855.
The product of its (nonzero) digits is 34560, while the sum is 34.
Adding to 11314031444035 its reverse (53044413041311), we get a palindrome (64358444485346).
The spelling of 11314031444035 in words is "eleven trillion, three hundred fourteen billion, thirty-one million, four hundred forty-four thousand, thirty-five".
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