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11314031444035 = 5109509116335069
BaseRepresentation
bin1010010010100100000011…
…0100110100000001000011
31111001121111022012220201221
42210221000310310001003
52440332114022202120
640021332211135511
72245261150336045
oct244510064640103
944047438186657
1011314031444035
113672287880851
12132889a2a4597
13640ba7220b68
142b1860017a95
15149485b0d0aa
hexa4a40d34043

11314031444035 has 32 divisors (see below), whose sum is σ = 13740510168000. Its totient is φ = 8942616055296.

The previous prime is 11314031444003. The next prime is 11314031444057. The reversal of 11314031444035 is 53044413041311.

It is a cyclic number.

It is not a de Polignac number, because 11314031444035 - 25 = 11314031444003 is a prime.

It is a super-2 number, since 2×113140314440352 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 322604481 + ... + 322639549.

It is an arithmetic number, because the mean of its divisors is an integer number (429390942750).

Almost surely, 211314031444035 is an apocalyptic number.

11314031444035 is a deficient number, since it is larger than the sum of its proper divisors (2426478723965).

11314031444035 is a wasteful number, since it uses less digits than its factorization.

11314031444035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36855.

The product of its (nonzero) digits is 34560, while the sum is 34.

Adding to 11314031444035 its reverse (53044413041311), we get a palindrome (64358444485346).

The spelling of 11314031444035 in words is "eleven trillion, three hundred fourteen billion, thirty-one million, four hundred forty-four thousand, thirty-five".

Divisors: 1 5 109 509 545 1163 2545 5815 35069 55481 126767 175345 277405 591967 633835 2959835 3822521 17850121 19112605 40785247 64524403 89250605 203926235 322622015 1945663189 4445591923 9728315945 20759690723 22227959615 103798453615 2262806288807 11314031444035