Base | Representation |
---|---|
bin | 1010010010100100000011… |
… | …0100110100000001000010 |
3 | 1111001121111022012220201220 |
4 | 2210221000310310001002 |
5 | 2440332114022202114 |
6 | 40021332211135510 |
7 | 2245261150336044 |
oct | 244510064640102 |
9 | 44047438186656 |
10 | 11314031444034 |
11 | 3672287880850 |
12 | 132889a2a4596 |
13 | 640ba7220b67 |
14 | 2b1860017a94 |
15 | 149485b0d0a9 |
hex | a4a40d34042 |
11314031444034 has 32 divisors (see below), whose sum is σ = 24755089195584. Its totient is φ = 3418781921280.
The previous prime is 11314031444003. The next prime is 11314031444057. The reversal of 11314031444034 is 43044413041311.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a junction number, because it is equal to n+sod(n) for n = 11314031443986 and 11314031444004.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 242787919 + ... + 242834514.
It is an arithmetic number, because the mean of its divisors is an integer number (773596537362).
Almost surely, 211314031444034 is an apocalyptic number.
11314031444034 is an abundant number, since it is smaller than the sum of its proper divisors (13441057751550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11314031444034 is a wasteful number, since it uses less digits than its factorization.
11314031444034 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 485622802.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 11314031444034 its reverse (43044413041311), we get a palindrome (54358444485345).
The spelling of 11314031444034 in words is "eleven trillion, three hundred fourteen billion, thirty-one million, four hundred forty-four thousand, thirty-four".
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