Base | Representation |
---|---|
bin | 10000011101101101000… |
… | …000000010100001110110 |
3 | 11000011100120100110021022 |
4 | 100131231000002201312 |
5 | 122014104203011000 |
6 | 2223432122221142 |
7 | 144512162614634 |
oct | 20355500024166 |
9 | 4004316313238 |
10 | 1131405125750 |
11 | 3a690a774879 |
12 | 1633353547b2 |
13 | 828ca2c4c13 |
14 | 3ca9039a354 |
15 | 1e66cb33585 |
hex | 1076d002876 |
1131405125750 has 32 divisors (see below), whose sum is σ = 2120069371680. Its totient is φ = 452117824800.
The previous prime is 1131405125723. The next prime is 1131405125777. The reversal of 1131405125750 is 575215041311.
It is an interprime number because it is at equal distance from previous prime (1131405125723) and next prime (1131405125777).
It is a super-3 number, since 3×11314051257503 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1131405125750.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1965869 + ... + 2475368.
It is an arithmetic number, because the mean of its divisors is an integer number (66252167865).
Almost surely, 21131405125750 is an apocalyptic number.
1131405125750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1131405125750 is a deficient number, since it is larger than the sum of its proper divisors (988664245930).
1131405125750 is a wasteful number, since it uses less digits than its factorization.
1131405125750 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4442273 (or 4442263 counting only the distinct ones).
The product of its (nonzero) digits is 21000, while the sum is 35.
The spelling of 1131405125750 in words is "one trillion, one hundred thirty-one billion, four hundred five million, one hundred twenty-five thousand, seven hundred fifty".
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