Base | Representation |
---|---|
bin | 10101000100110001… |
… | …01011010011010000 |
3 | 1002012111212121210102 |
4 | 22202120223103100 |
5 | 141132430444100 |
6 | 5110412551532 |
7 | 550244032346 |
oct | 124230532320 |
9 | 32174777712 |
10 | 11314312400 |
11 | 48866a8406 |
12 | 22391825a8 |
13 | 10b4096b11 |
14 | 79492b996 |
15 | 463478cd5 |
hex | 2a262b4d0 |
11314312400 has 30 divisors (see below), whose sum is σ = 27182636502. Its totient is φ = 4525724800.
The previous prime is 11314312369. The next prime is 11314312403. The reversal of 11314312400 is 421341311.
It can be written as a sum of positive squares in 3 ways, for example, as 2628817984 + 8685494416 = 51272^2 + 93196^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11314312403) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 14142491 + ... + 14143290.
Almost surely, 211314312400 is an apocalyptic number.
11314312400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11314312400 is an abundant number, since it is smaller than the sum of its proper divisors (15868324102).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11314312400 is a wasteful number, since it uses less digits than its factorization.
11314312400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28285799 (or 28285788 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 11314312400 its reverse (421341311), we get a palindrome (11735653711).
The spelling of 11314312400 in words is "eleven billion, three hundred fourteen million, three hundred twelve thousand, four hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.096 sec. • engine limits •