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11314408543 is a prime number
BaseRepresentation
bin10101000100110010…
…00010110001011111
31002012112001111200021
422202121002301133
5141132442033133
65110415013011
7550244612554
oct124231026137
932175044607
1011314408543
114886763669
12223920a167
1310b40cb7c9
14794954a2b
1546349752d
hex2a2642c5f

11314408543 has 2 divisors, whose sum is σ = 11314408544. Its totient is φ = 11314408542.

The previous prime is 11314408541. The next prime is 11314408549. The reversal of 11314408543 is 34580441311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11314408543 - 21 = 11314408541 is a prime.

It is a super-2 number, since 2×113144085432 (a number of 21 digits) contains 22 as substring.

Together with 11314408541, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11314408499 and 11314408508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11314408541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5657204271 + 5657204272.

It is an arithmetic number, because the mean of its divisors is an integer number (5657204272).

Almost surely, 211314408543 is an apocalyptic number.

11314408543 is a deficient number, since it is larger than the sum of its proper divisors (1).

11314408543 is an equidigital number, since it uses as much as digits as its factorization.

11314408543 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 34.

Adding to 11314408543 its reverse (34580441311), we get a palindrome (45894849854).

The spelling of 11314408543 in words is "eleven billion, three hundred fourteen million, four hundred eight thousand, five hundred forty-three".