Base | Representation |
---|---|
bin | 10101000100111110… |
… | …01100001100011101 |
3 | 1002012122002101011202 |
4 | 22202133030030131 |
5 | 141133400114442 |
6 | 5110513325245 |
7 | 550264403642 |
oct | 124237141435 |
9 | 32178071152 |
10 | 11316019997 |
11 | 4887664347 |
12 | 2239866825 |
13 | 10b4544129 |
14 | 794c53dc9 |
15 | 4636b4c32 |
hex | 2a27cc31d |
11316019997 has 2 divisors, whose sum is σ = 11316019998. Its totient is φ = 11316019996.
The previous prime is 11316019969. The next prime is 11316019999. The reversal of 11316019997 is 79991061311.
11316019997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11199142276 + 116877721 = 105826^2 + 10811^2 .
It is a cyclic number.
It is not a de Polignac number, because 11316019997 - 214 = 11316003613 is a prime.
Together with 11316019999, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11316019999) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5658009998 + 5658009999.
It is an arithmetic number, because the mean of its divisors is an integer number (5658009999).
Almost surely, 211316019997 is an apocalyptic number.
It is an amenable number.
11316019997 is a deficient number, since it is larger than the sum of its proper divisors (1).
11316019997 is an equidigital number, since it uses as much as digits as its factorization.
11316019997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 91854, while the sum is 47.
The spelling of 11316019997 in words is "eleven billion, three hundred sixteen million, nineteen thousand, nine hundred ninety-seven".
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