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1131911437133 is a prime number
BaseRepresentation
bin10000011110001011001…
…011011101101101001101
311000012122212001201220202
4100132023023131231031
5122021123311442013
62223554250223245
7144530551316261
oct20361313355515
94005585051822
101131911437133
113a704a552034
12163456a24b25
138297b179959
143cadb7160a1
151e69c2e6858
hex1078b2ddb4d

1131911437133 has 2 divisors, whose sum is σ = 1131911437134. Its totient is φ = 1131911437132.

The previous prime is 1131911437109. The next prime is 1131911437147. The reversal of 1131911437133 is 3317341191311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1118714482249 + 13196954884 = 1057693^2 + 114878^2 .

It is a cyclic number.

It is not a de Polignac number, because 1131911437133 - 216 = 1131911371597 is a prime.

It is a super-2 number, since 2×11319114371332 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1131911437633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565955718566 + 565955718567.

It is an arithmetic number, because the mean of its divisors is an integer number (565955718567).

Almost surely, 21131911437133 is an apocalyptic number.

It is an amenable number.

1131911437133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1131911437133 is an equidigital number, since it uses as much as digits as its factorization.

1131911437133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 20412, while the sum is 38.

The spelling of 1131911437133 in words is "one trillion, one hundred thirty-one billion, nine hundred eleven million, four hundred thirty-seven thousand, one hundred thirty-three".