Base | Representation |
---|---|
bin | 11001101111010010110000… |
… | …000000111111011101001110 |
3 | 112211210220212001211122021001 |
4 | 121233102300000333131032 |
5 | 104314141333420301220 |
6 | 1040431512244130514 |
7 | 32562340030120126 |
oct | 3157226000773516 |
9 | 484726761748231 |
10 | 113201111103310 |
11 | 3308435a08646a |
12 | 10843173096a3a |
13 | 4b21a8538acb9 |
14 | 1dd4d6a707c86 |
15 | d14949c0680a |
hex | 66f4b003f74e |
113201111103310 has 32 divisors (see below), whose sum is σ = 215748550708992. Its totient is φ = 42616780101120.
The previous prime is 113201111103281. The next prime is 113201111103337. The reversal of 113201111103310 is 13301111102311.
It is a super-2 number, since 2×1132011111033102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 103559715 + ... + 104647105.
It is an arithmetic number, because the mean of its divisors is an integer number (6742142209656).
Almost surely, 2113201111103310 is an apocalyptic number.
113201111103310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113201111103310 is a deficient number, since it is larger than the sum of its proper divisors (102547439605682).
113201111103310 is a wasteful number, since it uses less digits than its factorization.
113201111103310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1699788.
The product of its (nonzero) digits is 54, while the sum is 19.
Adding to 113201111103310 its reverse (13301111102311), we get a palindrome (126502222205621).
Subtracting from 113201111103310 its reverse (13301111102311), we obtain a palindrome (99900000000999).
The spelling of 113201111103310 in words is "one hundred thirteen trillion, two hundred one billion, one hundred eleven million, one hundred three thousand, three hundred ten".
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