Base | Representation |
---|---|
bin | 10101000101100101… |
… | …11111110100110100 |
3 | 1002012222212011120000 |
4 | 22202302333310310 |
5 | 141141212242322 |
6 | 5111220511300 |
7 | 550356500412 |
oct | 124262776464 |
9 | 32188764500 |
10 | 11321212212 |
11 | 488a590332 |
12 | 223b54b530 |
13 | 10b564154b |
14 | 7958062b2 |
15 | 463d8d3ac |
hex | 2a2cbfd34 |
11321212212 has 120 divisors (see below), whose sum is σ = 30675358560. Its totient is φ = 3636601920.
The previous prime is 11321212211. The next prime is 11321212267. The reversal of 11321212212 is 21221212311.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a nude number because it is divisible by every one of its digits.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11321212211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 7393887 + ... + 7395417.
It is an arithmetic number, because the mean of its divisors is an integer number (255627988).
Almost surely, 211321212212 is an apocalyptic number.
11321212212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11321212212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15337679280).
11321212212 is an abundant number, since it is smaller than the sum of its proper divisors (19354146348).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11321212212 is a wasteful number, since it uses less digits than its factorization.
11321212212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2363 (or 2352 counting only the distinct ones).
The product of its digits is 96, while the sum is 18.
Adding to 11321212212 its reverse (21221212311), we get a palindrome (32542424523).
Subtracting 11321212212 from its reverse (21221212311), we obtain a palindrome (9900000099).
The spelling of 11321212212 in words is "eleven billion, three hundred twenty-one million, two hundred twelve thousand, two hundred twelve".
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