Base | Representation |
---|---|
bin | 1010010011000110100101… |
… | …1101011010111000100110 |
3 | 1111002111102110111110110021 |
4 | 2210301221131122320212 |
5 | 2441010111044042410 |
6 | 40025504215145354 |
7 | 2246040002246464 |
oct | 244615135327046 |
9 | 44074373443407 |
10 | 11323303112230 |
11 | 367620545534a |
12 | 132a64737525a |
13 | 641a2405c365 |
14 | 2b209d549834 |
15 | 149829a9deda |
hex | a4c6975ae26 |
11323303112230 has 32 divisors (see below), whose sum is σ = 21039657838848. Its totient is φ = 4383166166400.
The previous prime is 11323303112201. The next prime is 11323303112293. The reversal of 11323303112230 is 3221130332311.
11323303112230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11323303112195 and 11323303112204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 43783500 + ... + 44041360.
It is an arithmetic number, because the mean of its divisors is an integer number (657489307464).
Almost surely, 211323303112230 is an apocalyptic number.
11323303112230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11323303112230 is a deficient number, since it is larger than the sum of its proper divisors (9716354726618).
11323303112230 is a wasteful number, since it uses less digits than its factorization.
11323303112230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 399552.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11323303112230 its reverse (3221130332311), we get a palindrome (14544433444541).
The spelling of 11323303112230 in words is "eleven trillion, three hundred twenty-three billion, three hundred three million, one hundred twelve thousand, two hundred thirty".
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