Base | Representation |
---|---|
bin | 11001101111110111010101… |
… | …111101100100111001001111 |
3 | 112211221200021100102202100202 |
4 | 121233313111331210321033 |
5 | 104320312321011313301 |
6 | 1040501531150044115 |
7 | 32565230511050252 |
oct | 3157672575447117 |
9 | 484850240382322 |
10 | 113240402447951 |
11 | 33099a92013219 |
12 | 1084a8b97a963b |
13 | 4b256a769065c |
14 | 1dd6c16b27099 |
15 | d159993ab66b |
hex | 66fdd5f64e4f |
113240402447951 has 2 divisors, whose sum is σ = 113240402447952. Its totient is φ = 113240402447950.
The previous prime is 113240402447947. The next prime is 113240402447959. The reversal of 113240402447951 is 159744204042311.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 113240402447951 - 22 = 113240402447947 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 113240402447896 and 113240402447905.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113240402447959) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56620201223975 + 56620201223976.
It is an arithmetic number, because the mean of its divisors is an integer number (56620201223976).
Almost surely, 2113240402447951 is an apocalyptic number.
113240402447951 is a deficient number, since it is larger than the sum of its proper divisors (1).
113240402447951 is an equidigital number, since it uses as much as digits as its factorization.
113240402447951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 967680, while the sum is 47.
The spelling of 113240402447951 in words is "one hundred thirteen trillion, two hundred forty billion, four hundred two million, four hundred forty-seven thousand, nine hundred fifty-one".
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