113242130000 has 50 divisors (see below), whose sum is σ = 274170545154. Its totient is φ = 45296848000.

The previous prime is 113242129997. The next prime is 113242130017. The reversal of 113242130000 is 31242311.

113242130000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 5 ways, for example, as 59866344976 + 53375785024 = 244676^2 + 231032^2 .

It is a tau number, because it is divible by the number of its divisors (50).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 5652107 + ... + 5672106.

Almost surely, 2^113242130000 is an apocalyptic number.

113242130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113242130000 is an abundant number, since it is smaller than the sum of its proper divisors (160928415154).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113242130000 is an equidigital number, since it uses as much as digits as its factorization.

113242130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11324241 (or 11324220 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 113242130000 its reverse (31242311), we get a palindrome (113273372311).

The spelling of 113242130000 in words is "one hundred thirteen billion, two hundred forty-two million, one hundred thirty thousand".