11325514001031 has 24 divisors (see below), whose sum is σ = 17338541463360. Its totient is φ = 7099161947136.

The previous prime is 11325514000987. The next prime is 11325514001057. The reversal of 11325514001031 is 13010041552311.

11325514001031 is a `hidden beast` number, since 1 + 1 + 3 + 2 + 551 + 4 + 0 + 0 + 103 + 1 = 666.

It is not a de Polignac number, because 11325514001031 - 2⁷ = 11325514000903 is a prime.

It is a super-2 number, since 2×11325514001031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11325514000986 and 11325514001004.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11325514001531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 36526975 + ... + 36835728.

It is an arithmetic number, because the mean of its divisors is an integer number (722439227640).

Almost surely, 2^{11325514001031} is an apocalyptic number.

11325514001031 is a deficient number, since it is larger than the sum of its proper divisors (6013027462329).

11325514001031 is a wasteful number, since it uses less digits than its factorization.

11325514001031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 73363735 (or 73363732 counting only the distinct ones).

The product of its (nonzero) digits is 1800, while the sum is 27.

Adding to 11325514001031 its reverse (13010041552311), we get a palindrome (24335555553342).

The spelling of 11325514001031 in words is "eleven trillion, three hundred twenty-five billion, five hundred fourteen million, one thousand, thirty-one".