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113257344797 is a prime number
BaseRepresentation
bin110100101111010101…
…0011110111100011101
3101211100002200020101222
41221132222132330131
53323422340013142
6124010225543125
711116423355342
oct1513652367435
9354302606358
10113257344797
1144039900503
1219b497a4aa5
13a8ac2c5c6c
1456a5a587c9
152e2d071bd2
hex1a5ea9ef1d

113257344797 has 2 divisors, whose sum is σ = 113257344798. Its totient is φ = 113257344796.

The previous prime is 113257344743. The next prime is 113257344799. The reversal of 113257344797 is 797443752311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68738876761 + 44518468036 = 262181^2 + 210994^2 .

It is a cyclic number.

It is not a de Polignac number, because 113257344797 - 212 = 113257340701 is a prime.

Together with 113257344799, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113257344799) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56628672398 + 56628672399.

It is an arithmetic number, because the mean of its divisors is an integer number (56628672399).

Almost surely, 2113257344797 is an apocalyptic number.

It is an amenable number.

113257344797 is a deficient number, since it is larger than the sum of its proper divisors (1).

113257344797 is an equidigital number, since it uses as much as digits as its factorization.

113257344797 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4445280, while the sum is 53.

The spelling of 113257344797 in words is "one hundred thirteen billion, two hundred fifty-seven million, three hundred forty-four thousand, seven hundred ninety-seven".