Base | Representation |
---|---|
bin | 11001110000101110111110… |
… | …001000001001111110010110 |
3 | 112212011101110000022222110210 |
4 | 121300232332020021332112 |
5 | 104322302132310011410 |
6 | 1040545210120030250 |
7 | 32602443615566322 |
oct | 3160567610117626 |
9 | 485141400288423 |
10 | 113300132110230 |
11 | 3311235293657a |
12 | 1085a3a9002386 |
13 | 4b2b2061070a0 |
14 | 1dd9a81728982 |
15 | d172e300e220 |
hex | 670bbe209f96 |
113300132110230 has 128 divisors (see below), whose sum is σ = 297097679241216. Its totient is φ = 27486418176000.
The previous prime is 113300132110201. The next prime is 113300132110247. The reversal of 113300132110230 is 32011231003311.
It is a happy number.
It is a super-2 number, since 2×1133001321102302 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 113300132110197 and 113300132110206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 95491 + ... + 15053550.
It is an arithmetic number, because the mean of its divisors is an integer number (2321075619072).
Almost surely, 2113300132110230 is an apocalyptic number.
113300132110230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 113300132110230, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (148548839620608).
113300132110230 is an abundant number, since it is smaller than the sum of its proper divisors (183797547130986).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113300132110230 is a wasteful number, since it uses less digits than its factorization.
113300132110230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15149342.
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 113300132110230 its reverse (32011231003311), we get a palindrome (145311363113541).
The spelling of 113300132110230 in words is "one hundred thirteen trillion, three hundred billion, one hundred thirty-two million, one hundred ten thousand, two hundred thirty".
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