Base | Representation |
---|---|
bin | 11001110000111001010010… |
… | …100010101000011011111110 |
3 | 112212012110001012010101010112 |
4 | 121300321102202220123332 |
5 | 104322442330233411220 |
6 | 1040554241400510022 |
7 | 32603315315322623 |
oct | 3160712242503376 |
9 | 485173035111115 |
10 | 113311212013310 |
11 | 33117019189773 |
12 | 1086057b77b312 |
13 | 4b2c28075995c |
14 | 1dda41307834a |
15 | d17740ad35c5 |
hex | 670e528a86fe |
113311212013310 has 64 divisors (see below), whose sum is σ = 204739009413120. Its totient is φ = 45151785317760.
The previous prime is 113311212013273. The next prime is 113311212013331. The reversal of 113311212013310 is 13310212113311.
It is a super-2 number, since 2×1133112120133102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 18738414707 + ... + 18738420753.
It is an arithmetic number, because the mean of its divisors is an integer number (3199047022080).
Almost surely, 2113311212013310 is an apocalyptic number.
113311212013310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113311212013310 is a deficient number, since it is larger than the sum of its proper divisors (91427797399810).
113311212013310 is a wasteful number, since it uses less digits than its factorization.
113311212013310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12641.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 113311212013310 its reverse (13310212113311), we get a palindrome (126621424126621).
The spelling of 113311212013310 in words is "one hundred thirteen trillion, three hundred eleven billion, two hundred twelve million, thirteen thousand, three hundred ten".
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