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11331131232103 is a prime number
BaseRepresentation
bin1010010011100011110000…
…0011010100111101100111
31111010020122000111011010221
42210320330003110331213
52441122124043411403
640033241055025211
72246434665210424
oct244707403247547
944106560434127
1011331131232103
1136795621a6701
121330070b0b207
136426a0ab2457
142b2603070d4b
15149b36e46dbd
hexa4e3c0d4f67

11331131232103 has 2 divisors, whose sum is σ = 11331131232104. Its totient is φ = 11331131232102.

The previous prime is 11331131232067. The next prime is 11331131232143. The reversal of 11331131232103 is 30123213113311.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11331131232103 - 225 = 11331097677671 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131232143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565616051 + 5665565616052.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565616052).

Almost surely, 211331131232103 is an apocalyptic number.

11331131232103 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131232103 is an equidigital number, since it uses as much as digits as its factorization.

11331131232103 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11331131232103 its reverse (30123213113311), we get a palindrome (41454344345414).

The spelling of 11331131232103 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, two hundred thirty-two thousand, one hundred three".