11331131320122 has 24 divisors (see below), whose sum is σ = 23917789660896. Its totient is φ = 3578251995144.

The previous prime is 11331131320037. The next prime is 11331131320139. The reversal of 11331131320122 is 22102313113311.

11331131320122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a junction number, because it is equal to n+sod(n) for n = 11331131320092 and 11331131320101.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2615679118 + ... + 2615683449.

It is an arithmetic number, because the mean of its divisors is an integer number (996574569204).

Almost surely, 2^{11331131320122} is an apocalyptic number.

11331131320122 is an abundant number, since it is smaller than the sum of its proper divisors (12586658340774).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11331131320122 is a wasteful number, since it uses less digits than its factorization.

11331131320122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5231362610 (or 5231362591 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 11331131320122 its reverse (22102313113311), we get a palindrome (33433444433433).

The spelling of 11331131320122 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred twenty thousand, one hundred twenty-two".