11331131322031 has 2 divisors, whose sum is σ = 11331131322032. Its totient is φ = 11331131322030.

The previous prime is 11331131321989. The next prime is 11331131322059. The reversal of 11331131322031 is 13022313113311.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11331131322031 is a prime.

It is a super-2 number, since 2×11331131322031² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11331131321987 and 11331131322005.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11331131320031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5665565661015 + 5665565661016.

It is an arithmetic number, because the mean of its divisors is an integer number (5665565661016).

Almost surely, 2^{11331131322031} is an apocalyptic number.

11331131322031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11331131322031 is an equidigital number, since it uses as much as digits as its factorization.

11331131322031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 11331131322031 its reverse (13022313113311), we get a palindrome (24353444435342).

The spelling of 11331131322031 in words is "eleven trillion, three hundred thirty-one billion, one hundred thirty-one million, three hundred twenty-two thousand, thirty-one".