Base | Representation |
---|---|
bin | 1010010011100100001000… |
… | …0100000111101001110110 |
3 | 1111010020220001021221001012 |
4 | 2210321002010013221312 |
5 | 2441122330404244110 |
6 | 40033255101032222 |
7 | 2246440331460650 |
oct | 244710204075166 |
9 | 44106801257035 |
10 | 11331232103030 |
11 | 3679604132504 |
12 | 133009a855672 |
13 | 6426b896c4a8 |
14 | 2b261260b6d0 |
15 | 149b40c1e905 |
hex | a4e42107a76 |
11331232103030 has 64 divisors (see below), whose sum is σ = 23453422829568. Its totient is φ = 3861155640960.
The previous prime is 11331232103021. The next prime is 11331232103071. The reversal of 11331232103030 is 3030123213311.
It is a junction number, because it is equal to n+sod(n) for n = 11331232102987 and 11331232103005.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6840500 + ... + 8333960.
It is an arithmetic number, because the mean of its divisors is an integer number (366459731712).
Almost surely, 211331232103030 is an apocalyptic number.
11331232103030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11331232103030 is an abundant number, since it is smaller than the sum of its proper divisors (12122190726538).
11331232103030 is a wasteful number, since it uses less digits than its factorization.
11331232103030 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1494141.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 11331232103030 its reverse (3030123213311), we get a palindrome (14361355316341).
The spelling of 11331232103030 in words is "eleven trillion, three hundred thirty-one billion, two hundred thirty-two million, one hundred three thousand, thirty".
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