1133130094841 has 2 divisors, whose sum is σ = 1133130094842. Its totient is φ = 1133130094840.

The previous prime is 1133130094829. The next prime is 1133130094843. The reversal of 1133130094841 is 1484900313311.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1014091294441 + 119038800400 = 1007021^2 + 345020^2 .

It is a cyclic number.

It is not a de Polignac number, because 1133130094841 - 2³⁰ = 1132056353017 is a prime.

Together with 1133130094843, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1133130094795 and 1133130094804.

It is not a weakly prime, because it can be changed into another prime (1133130094843) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566565047420 + 566565047421.

It is an arithmetic number, because the mean of its divisors is an integer number (566565047421).

Almost surely, 2^{1133130094841} is an apocalyptic number.

It is an amenable number.

1133130094841 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133130094841 is an equidigital number, since it uses as much as digits as its factorization.

1133130094841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 38.

The spelling of 1133130094841 in words is "one trillion, one hundred thirty-three billion, one hundred thirty million, ninety-four thousand, eight hundred forty-one".