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1133131311223 is a prime number
BaseRepresentation
bin10000011111010011111…
…000111010100001110111
311000022210212110202120121
4100133103320322201313
5122031123103424343
62224315304312411
7144603023140432
oct20372370724167
94008725422517
101133131311223
113a76160a253a
12163737472707
1382b13b0c142
143cbb573a819
151e71e45aaed
hex107d3e3a877

1133131311223 has 2 divisors, whose sum is σ = 1133131311224. Its totient is φ = 1133131311222.

The previous prime is 1133131311209. The next prime is 1133131311241. The reversal of 1133131311223 is 3221131313311.

It is a weak prime.

It is an emirp because it is prime and its reverse (3221131313311) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1133131311223 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1133131311283) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 566565655611 + 566565655612.

It is an arithmetic number, because the mean of its divisors is an integer number (566565655612).

Almost surely, 21133131311223 is an apocalyptic number.

1133131311223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1133131311223 is an equidigital number, since it uses as much as digits as its factorization.

1133131311223 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 25.

Adding to 1133131311223 its reverse (3221131313311), we get a palindrome (4354262624534).

The spelling of 1133131311223 in words is "one trillion, one hundred thirty-three billion, one hundred thirty-one million, three hundred eleven thousand, two hundred twenty-three".