Base | Representation |
---|---|
bin | 11001110000111011000100… |
… | …111011110010101000100100 |
3 | 112212012121222221102201211120 |
4 | 121300323010323302220210 |
5 | 104323010243042230200 |
6 | 1040555200035533540 |
7 | 32603414011251216 |
oct | 3160730473625044 |
9 | 485177887381746 |
10 | 113313131211300 |
11 | 33117913557609 |
12 | 10860a1645a2b0 |
13 | 4b2c4c8252877 |
14 | 1dda555cdc5b6 |
15 | d178043349a0 |
hex | 670ec4ef2a24 |
113313131211300 has 72 divisors (see below), whose sum is σ = 327854190468000. Its totient is φ = 30216693899520.
The previous prime is 113313131211221. The next prime is 113313131211323. The reversal of 113313131211300 is 3112131313311.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 74077611 + ... + 75591789.
Almost surely, 2113313131211300 is an apocalyptic number.
113313131211300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
113313131211300 is an abundant number, since it is smaller than the sum of its proper divisors (214541059256700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113313131211300 is a wasteful number, since it uses less digits than its factorization.
113313131211300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1763645 (or 1763638 counting only the distinct ones).
The product of its (nonzero) digits is 486, while the sum is 24.
Adding to 113313131211300 its reverse (3112131313311), we get a palindrome (116425262524611).
The spelling of 113313131211300 in words is "one hundred thirteen trillion, three hundred thirteen billion, one hundred thirty-one million, two hundred eleven thousand, three hundred".
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