Base | Representation |
---|---|
bin | 110100110001000001… |
… | …1100010000010111111 |
3 | 101211111001201221201121 |
4 | 1221202003202002333 |
5 | 3324031421232001 |
6 | 124020021251411 |
7 | 11121014112523 |
oct | 1514203420277 |
9 | 354431657647 |
10 | 113314242751 |
11 | 44068a32806 |
12 | 19b64863b67 |
13 | a8bb027ca8 |
14 | 56ad429d83 |
15 | 2e330606a1 |
hex | 1a620e20bf |
113314242751 has 2 divisors, whose sum is σ = 113314242752. Its totient is φ = 113314242750.
The previous prime is 113314242739. The next prime is 113314242763. The reversal of 113314242751 is 157242413311.
It is a balanced prime because it is at equal distance from previous prime (113314242739) and next prime (113314242763).
It is a cyclic number.
It is not a de Polignac number, because 113314242751 - 221 = 113312145599 is a prime.
It is a super-2 number, since 2×1133142427512 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113314242731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56657121375 + 56657121376.
It is an arithmetic number, because the mean of its divisors is an integer number (56657121376).
Almost surely, 2113314242751 is an apocalyptic number.
113314242751 is a deficient number, since it is larger than the sum of its proper divisors (1).
113314242751 is an equidigital number, since it uses as much as digits as its factorization.
113314242751 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 20160, while the sum is 34.
The spelling of 113314242751 in words is "one hundred thirteen billion, three hundred fourteen million, two hundred forty-two thousand, seven hundred fifty-one".
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