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11333413100143 is a prime number
BaseRepresentation
bin1010010011101100010000…
…0011111101101001101111
31111010110112001020001122001
42210323010003331221233
52441141312223201033
640034255331233131
72246545353603061
oct244730403755157
944113461201561
1011333413100143
11367a523262962
1213305a91487a7
13642975779524
142b277c13d731
15149c1c435e7d
hexa4ec40fda6f

11333413100143 has 2 divisors, whose sum is σ = 11333413100144. Its totient is φ = 11333413100142.

The previous prime is 11333413100129. The next prime is 11333413100171. The reversal of 11333413100143 is 34100131433311.

It is a happy number.

It is an a-pointer prime, because the next prime (11333413100171) can be obtained adding 11333413100143 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11333413100143 - 25 = 11333413100111 is a prime.

It is a super-2 number, since 2×113334131001432 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11333413100183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666706550071 + 5666706550072.

It is an arithmetic number, because the mean of its divisors is an integer number (5666706550072).

Almost surely, 211333413100143 is an apocalyptic number.

11333413100143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11333413100143 is an equidigital number, since it uses as much as digits as its factorization.

11333413100143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 11333413100143 its reverse (34100131433311), we get a palindrome (45433544533454).

The spelling of 11333413100143 in words is "eleven trillion, three hundred thirty-three billion, four hundred thirteen million, one hundred thousand, one hundred forty-three".