Base | Representation |
---|---|
bin | 1010010011101100010000… |
… | …0011111101101001101111 |
3 | 1111010110112001020001122001 |
4 | 2210323010003331221233 |
5 | 2441141312223201033 |
6 | 40034255331233131 |
7 | 2246545353603061 |
oct | 244730403755157 |
9 | 44113461201561 |
10 | 11333413100143 |
11 | 367a523262962 |
12 | 13305a91487a7 |
13 | 642975779524 |
14 | 2b277c13d731 |
15 | 149c1c435e7d |
hex | a4ec40fda6f |
11333413100143 has 2 divisors, whose sum is σ = 11333413100144. Its totient is φ = 11333413100142.
The previous prime is 11333413100129. The next prime is 11333413100171. The reversal of 11333413100143 is 34100131433311.
It is a happy number.
It is an a-pointer prime, because the next prime (11333413100171) can be obtained adding 11333413100143 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11333413100143 - 25 = 11333413100111 is a prime.
It is a super-2 number, since 2×113334131001432 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11333413100183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5666706550071 + 5666706550072.
It is an arithmetic number, because the mean of its divisors is an integer number (5666706550072).
Almost surely, 211333413100143 is an apocalyptic number.
11333413100143 is a deficient number, since it is larger than the sum of its proper divisors (1).
11333413100143 is an equidigital number, since it uses as much as digits as its factorization.
11333413100143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 28.
Adding to 11333413100143 its reverse (34100131433311), we get a palindrome (45433544533454).
The spelling of 11333413100143 in words is "eleven trillion, three hundred thirty-three billion, four hundred thirteen million, one hundred thousand, one hundred forty-three".
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