Base | Representation |
---|---|
bin | 1010010011101100010000… |
… | …0011111101101011000110 |
3 | 1111010110112001020001202021 |
4 | 2210323010003331223012 |
5 | 2441141312223201410 |
6 | 40034255331233354 |
7 | 2246545353603244 |
oct | 244730403755306 |
9 | 44113461201667 |
10 | 11333413100230 |
11 | 367a523262a31 |
12 | 13305a914885a |
13 | 642975779590 |
14 | 2b277c13d794 |
15 | 149c1c435eda |
hex | a4ec40fdac6 |
11333413100230 has 32 divisors (see below), whose sum is σ = 22006433411424. Its totient is φ = 4177588071936.
The previous prime is 11333413100183. The next prime is 11333413100281. The reversal of 11333413100230 is 3200131433311.
11333413100230 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 11333413100195 and 11333413100204.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 73430584 + ... + 73584763.
It is an arithmetic number, because the mean of its divisors is an integer number (687701044107).
Almost surely, 211333413100230 is an apocalyptic number.
11333413100230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
11333413100230 is a deficient number, since it is larger than the sum of its proper divisors (10673020311194).
11333413100230 is a wasteful number, since it uses less digits than its factorization.
11333413100230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 147015960.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 11333413100230 its reverse (3200131433311), we get a palindrome (14533544533541).
The spelling of 11333413100230 in words is "eleven trillion, three hundred thirty-three billion, four hundred thirteen million, one hundred thousand, two hundred thirty".
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