Base | Representation |
---|---|
bin | 1010010011101111011010… |
… | …1011000110100011110111 |
3 | 1111010112201012222212112102 |
4 | 2210323312223012203313 |
5 | 2441200032112033142 |
6 | 40034515503012315 |
7 | 2246605404163163 |
oct | 244736653064367 |
9 | 44115635885472 |
10 | 11334262221047 |
11 | 367a9195a3a77 |
12 | 13307a559a09b |
13 | 642a7c66a62c |
14 | 2b281cc13ca3 |
15 | 149c6bc62532 |
hex | a4ef6ac68f7 |
11334262221047 has 2 divisors, whose sum is σ = 11334262221048. Its totient is φ = 11334262221046.
The previous prime is 11334262220951. The next prime is 11334262221049. The reversal of 11334262221047 is 74012226243311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11334262221047 - 212 = 11334262216951 is a prime.
Together with 11334262221049, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11334262221047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11334262221049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5667131110523 + 5667131110524.
It is an arithmetic number, because the mean of its divisors is an integer number (5667131110524).
Almost surely, 211334262221047 is an apocalyptic number.
11334262221047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11334262221047 is an equidigital number, since it uses as much as digits as its factorization.
11334262221047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96768, while the sum is 38.
Adding to 11334262221047 its reverse (74012226243311), we get a palindrome (85346488464358).
The spelling of 11334262221047 in words is "eleven trillion, three hundred thirty-four billion, two hundred sixty-two million, two hundred twenty-one thousand, forty-seven".
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