113412534343 has 2 divisors, whose sum is σ = 113412534344. Its totient is φ = 113412534342.

The previous prime is 113412534337. The next prime is 113412534349. The reversal of 113412534343 is 343435214311.

It is a balanced prime because it is at equal distance from previous prime (113412534337) and next prime (113412534349).

It is a cyclic number.

It is not a de Polignac number, because 113412534343 - 2⁵ = 113412534311 is a prime.

It is a super-2 number, since 2×113412534343² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 113412534299 and 113412534308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113412534349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56706267171 + 56706267172.

It is an arithmetic number, because the mean of its divisors is an integer number (56706267172).

Almost surely, 2^113412534343 is an apocalyptic number.

113412534343 is a deficient number, since it is larger than the sum of its proper divisors (1).

113412534343 is an equidigital number, since it uses as much as digits as its factorization.

113412534343 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 51840, while the sum is 34.

Adding to 113412534343 its reverse (343435214311), we get a palindrome (456847748654).

The spelling of 113412534343 in words is "one hundred thirteen billion, four hundred twelve million, five hundred thirty-four thousand, three hundred forty-three".