Base | Representation |
---|---|
bin | 110100110011111110… |
… | …0010000101101100111 |
3 | 101211201221120100020221 |
4 | 1221213330100231213 |
5 | 3324232212000124 |
6 | 124033510105211 |
7 | 11123323410613 |
oct | 1514774205547 |
9 | 354657510227 |
10 | 113413000039 |
11 | 441097555a9 |
12 | 19b9194b207 |
13 | a905624c61 |
14 | 56bc5b6343 |
15 | 2e3ba6bce4 |
hex | 1a67f10b67 |
113413000039 has 2 divisors, whose sum is σ = 113413000040. Its totient is φ = 113413000038.
The previous prime is 113413000033. The next prime is 113413000067. The reversal of 113413000039 is 930000314311.
It is a weak prime.
It is an emirp because it is prime and its reverse (930000314311) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 113413000039 - 27 = 113412999911 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 113412999977 and 113413000022.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (113413000033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56706500019 + 56706500020.
It is an arithmetic number, because the mean of its divisors is an integer number (56706500020).
Almost surely, 2113413000039 is an apocalyptic number.
113413000039 is a deficient number, since it is larger than the sum of its proper divisors (1).
113413000039 is an equidigital number, since it uses as much as digits as its factorization.
113413000039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 113413000039 in words is "one hundred thirteen billion, four hundred thirteen million, thirty-nine", and thus it is an aban number.
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