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113414202414311 is a prime number
BaseRepresentation
bin11001110010011001001101…
…001111110101010011100111
3112212120021212202201211100212
4121302121031033311103213
5104331134241304224221
61041113433150330035
732613622443304451
oct3162311517652347
9485507782654325
10113414202414311
1133156769619357
1210878522ab991b
134b38bb496c736
1420013c33232d1
15d1a26c617b5b
hex67264d3f54e7

113414202414311 has 2 divisors, whose sum is σ = 113414202414312. Its totient is φ = 113414202414310.

The previous prime is 113414202414301. The next prime is 113414202414313.

113414202414311 is nontrivially palindromic in base 10.

It is a strong prime.

It is a palprime.

It is a cyclic number.

It is not a de Polignac number, because 113414202414311 - 238 = 113139324507367 is a prime.

It is a super-2 number, since 2×1134142024143112 (a number of 29 digits) contains 22 as substring.

Together with 113414202414313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113414202414313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56707101207155 + 56707101207156.

It is an arithmetic number, because the mean of its divisors is an integer number (56707101207156).

Almost surely, 2113414202414311 is an apocalyptic number.

113414202414311 is a deficient number, since it is larger than the sum of its proper divisors (1).

113414202414311 is an equidigital number, since it uses as much as digits as its factorization.

113414202414311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 32.

It can be divided in two parts, 11341420 and 2414311, that added together give a palindrome (13755731).

The spelling of 113414202414311 in words is "one hundred thirteen trillion, four hundred fourteen billion, two hundred two million, four hundred fourteen thousand, three hundred eleven".