11341443437 has 2 divisors, whose sum is σ = 11341443438. Its totient is φ = 11341443436.

The previous prime is 11341443433. The next prime is 11341443439. The reversal of 11341443437 is 73434414311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6575750281 + 4765693156 = 81091^2 + 69034^2 .

It is a cyclic number.

It is not a de Polignac number, because 11341443437 - 2² = 11341443433 is a prime.

Together with 11341443439, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11341443397 and 11341443406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11341443433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670721718 + 5670721719.

It is an arithmetic number, because the mean of its divisors is an integer number (5670721719).

Almost surely, 2^11341443437 is an apocalyptic number.

It is an amenable number.

11341443437 is a deficient number, since it is larger than the sum of its proper divisors (1).

11341443437 is an equidigital number, since it uses as much as digits as its factorization.

11341443437 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48384, while the sum is 35.

Adding to 11341443437 its reverse (73434414311), we get a palindrome (84775857748).

The spelling of 11341443437 in words is "eleven billion, three hundred forty-one million, four hundred forty-three thousand, four hundred thirty-seven".