Base | Representation |
---|---|
bin | 10101001000000000… |
… | …01011000101101111 |
3 | 1002021101221000120201 |
4 | 22210000023011233 |
5 | 141211402142224 |
6 | 5113222254331 |
7 | 551023451524 |
oct | 124400130557 |
9 | 32241830521 |
10 | 11341443439 |
11 | 489aa49357 |
12 | 22462873a7 |
13 | 10b98a5ca1 |
14 | 79839114b |
15 | 465a37a44 |
hex | 2a400b16f |
11341443439 has 2 divisors, whose sum is σ = 11341443440. Its totient is φ = 11341443438.
The previous prime is 11341443437. The next prime is 11341443473. The reversal of 11341443439 is 93434414311.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11341443439 - 21 = 11341443437 is a prime.
It is a super-2 number, since 2×113414434392 (a number of 21 digits) contains 22 as substring.
Together with 11341443437, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 11341443398 and 11341443407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11341443433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5670721719 + 5670721720.
It is an arithmetic number, because the mean of its divisors is an integer number (5670721720).
Almost surely, 211341443439 is an apocalyptic number.
11341443439 is a deficient number, since it is larger than the sum of its proper divisors (1).
11341443439 is an equidigital number, since it uses as much as digits as its factorization.
11341443439 is an evil number, because the sum of its binary digits is even.
The product of its digits is 62208, while the sum is 37.
The spelling of 11341443439 in words is "eleven billion, three hundred forty-one million, four hundred forty-three thousand, four hundred thirty-nine".
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