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113416244111 is a prime number
BaseRepresentation
bin110100110100000100…
…0101000101110001111
3101211202011200011021202
41221220020220232033
53324234024302421
6124034103420115
711123363111552
oct1515010505617
9354664604252
10113416244111
1144110570955
1219b92a5463b
13a9061bc721
1456bcbbc699
152e3bead10b
hex1a68228b8f

113416244111 has 2 divisors, whose sum is σ = 113416244112. Its totient is φ = 113416244110.

The previous prime is 113416244093. The next prime is 113416244113. The reversal of 113416244111 is 111442614311.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-113416244111 is a prime.

Together with 113416244113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (113416244113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56708122055 + 56708122056.

It is an arithmetic number, because the mean of its divisors is an integer number (56708122056).

Almost surely, 2113416244111 is an apocalyptic number.

113416244111 is a deficient number, since it is larger than the sum of its proper divisors (1).

113416244111 is an equidigital number, since it uses as much as digits as its factorization.

113416244111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2304, while the sum is 29.

Adding to 113416244111 its reverse (111442614311), we get a palindrome (224858858422).

The spelling of 113416244111 in words is "one hundred thirteen billion, four hundred sixteen million, two hundred forty-four thousand, one hundred eleven".