1134303413140 has 24 divisors (see below), whose sum is σ = 2406594255912. Its totient is φ = 449043824640.

The previous prime is 1134303413137. The next prime is 1134303413183. The reversal of 1134303413140 is 413143034311.

It can be written as a sum of positive squares in 4 ways, for example, as 332626720644 + 801676692496 = 576738^2 + 895364^2 .

It is a super-2 number, since 2×1134303413140² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1134303413099 and 1134303413108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 292344301 + ... + 292348180.

It is an arithmetic number, because the mean of its divisors is an integer number (100274760663).

Almost surely, 2^{1134303413140} is an apocalyptic number.

1134303413140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1134303413140 is an abundant number, since it is smaller than the sum of its proper divisors (1272290842772).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1134303413140 is a wasteful number, since it uses less digits than its factorization.

1134303413140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 584692587 (or 584692585 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1134303413140 its reverse (413143034311), we get a palindrome (1547446447451).

The spelling of 1134303413140 in words is "one trillion, one hundred thirty-four billion, three hundred three million, four hundred thirteen thousand, one hundred forty".